3.43 \(\int \csc (c+d x) \sqrt{-a-a \sin (c+d x)} \, dx\)

Optimal. Leaf size=40 \[ \frac{2 \sqrt{a} \tan ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{a (-\sin (c+d x))-a}}\right )}{d} \]

[Out]

(2*Sqrt[a]*ArcTan[(Sqrt[a]*Cos[c + d*x])/Sqrt[-a - a*Sin[c + d*x]]])/d

________________________________________________________________________________________

Rubi [A]  time = 0.0525074, antiderivative size = 40, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.083, Rules used = {2773, 204} \[ \frac{2 \sqrt{a} \tan ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{a (-\sin (c+d x))-a}}\right )}{d} \]

Antiderivative was successfully verified.

[In]

Int[Csc[c + d*x]*Sqrt[-a - a*Sin[c + d*x]],x]

[Out]

(2*Sqrt[a]*ArcTan[(Sqrt[a]*Cos[c + d*x])/Sqrt[-a - a*Sin[c + d*x]]])/d

Rule 2773

Int[Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]]/((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Dist[(-2*
b)/f, Subst[Int[1/(b*c + a*d - d*x^2), x], x, (b*Cos[e + f*x])/Sqrt[a + b*Sin[e + f*x]]], x] /; FreeQ[{a, b, c
, d, e, f}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \csc (c+d x) \sqrt{-a-a \sin (c+d x)} \, dx &=\frac{(2 a) \operatorname{Subst}\left (\int \frac{1}{-a-x^2} \, dx,x,-\frac{a \cos (c+d x)}{\sqrt{-a-a \sin (c+d x)}}\right )}{d}\\ &=\frac{2 \sqrt{a} \tan ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{-a-a \sin (c+d x)}}\right )}{d}\\ \end{align*}

Mathematica [B]  time = 0.0851717, size = 95, normalized size = 2.38 \[ \frac{\sqrt{-a (\sin (c+d x)+1)} \left (\log \left (\sin \left (\frac{1}{2} (c+d x)\right )-\cos \left (\frac{1}{2} (c+d x)\right )+1\right )-\log \left (-\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )+1\right )\right )}{d \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )} \]

Antiderivative was successfully verified.

[In]

Integrate[Csc[c + d*x]*Sqrt[-a - a*Sin[c + d*x]],x]

[Out]

((-Log[1 + Cos[(c + d*x)/2] - Sin[(c + d*x)/2]] + Log[1 - Cos[(c + d*x)/2] + Sin[(c + d*x)/2]])*Sqrt[-(a*(1 +
Sin[c + d*x]))])/(d*(Cos[(c + d*x)/2] + Sin[(c + d*x)/2]))

________________________________________________________________________________________

Maple [A]  time = 0.447, size = 69, normalized size = 1.7 \begin{align*} -2\,{\frac{ \left ( 1+\sin \left ( dx+c \right ) \right ) \sqrt{a \left ( \sin \left ( dx+c \right ) -1 \right ) }\sqrt{a}}{\cos \left ( dx+c \right ) \sqrt{-a-a\sin \left ( dx+c \right ) }d}\arctan \left ({\frac{\sqrt{a \left ( \sin \left ( dx+c \right ) -1 \right ) }}{\sqrt{a}}} \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(csc(d*x+c)*(-a-a*sin(d*x+c))^(1/2),x)

[Out]

-2*(1+sin(d*x+c))*(a*(sin(d*x+c)-1))^(1/2)*a^(1/2)*arctan((a*(sin(d*x+c)-1))^(1/2)/a^(1/2))/cos(d*x+c)/(-a-a*s
in(d*x+c))^(1/2)/d

________________________________________________________________________________________

Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{-a \sin \left (d x + c\right ) - a} \csc \left (d x + c\right )\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(d*x+c)*(-a-a*sin(d*x+c))^(1/2),x, algorithm="maxima")

[Out]

integrate(sqrt(-a*sin(d*x + c) - a)*csc(d*x + c), x)

________________________________________________________________________________________

Fricas [A]  time = 1.52711, size = 589, normalized size = 14.72 \begin{align*} \left [\frac{\sqrt{-a} \log \left (\frac{a \cos \left (d x + c\right )^{3} - 7 \, a \cos \left (d x + c\right )^{2} + 4 \,{\left (\cos \left (d x + c\right )^{2} +{\left (\cos \left (d x + c\right ) + 3\right )} \sin \left (d x + c\right ) - 2 \, \cos \left (d x + c\right ) - 3\right )} \sqrt{-a \sin \left (d x + c\right ) - a} \sqrt{-a} - 9 \, a \cos \left (d x + c\right ) +{\left (a \cos \left (d x + c\right )^{2} + 8 \, a \cos \left (d x + c\right ) - a\right )} \sin \left (d x + c\right ) - a}{\cos \left (d x + c\right )^{3} + \cos \left (d x + c\right )^{2} +{\left (\cos \left (d x + c\right )^{2} - 1\right )} \sin \left (d x + c\right ) - \cos \left (d x + c\right ) - 1}\right )}{2 \, d}, \frac{\sqrt{a} \arctan \left (\frac{\sqrt{-a \sin \left (d x + c\right ) - a}{\left (\sin \left (d x + c\right ) - 2\right )}}{2 \, \sqrt{a} \cos \left (d x + c\right )}\right )}{d}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(d*x+c)*(-a-a*sin(d*x+c))^(1/2),x, algorithm="fricas")

[Out]

[1/2*sqrt(-a)*log((a*cos(d*x + c)^3 - 7*a*cos(d*x + c)^2 + 4*(cos(d*x + c)^2 + (cos(d*x + c) + 3)*sin(d*x + c)
- 2*cos(d*x + c) - 3)*sqrt(-a*sin(d*x + c) - a)*sqrt(-a) - 9*a*cos(d*x + c) + (a*cos(d*x + c)^2 + 8*a*cos(d*x
+ c) - a)*sin(d*x + c) - a)/(cos(d*x + c)^3 + cos(d*x + c)^2 + (cos(d*x + c)^2 - 1)*sin(d*x + c) - cos(d*x +
c) - 1))/d, sqrt(a)*arctan(1/2*sqrt(-a*sin(d*x + c) - a)*(sin(d*x + c) - 2)/(sqrt(a)*cos(d*x + c)))/d]

________________________________________________________________________________________

Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{- a \left (\sin{\left (c + d x \right )} + 1\right )} \csc{\left (c + d x \right )}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(d*x+c)*(-a-a*sin(d*x+c))**(1/2),x)

[Out]

Integral(sqrt(-a*(sin(c + d*x) + 1))*csc(c + d*x), x)

________________________________________________________________________________________

Giac [B]  time = 2.13265, size = 258, normalized size = 6.45 \begin{align*} \frac{2 \, \sqrt{a} \arctan \left (-\frac{\sqrt{-a} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - a}}{\sqrt{a}}\right ) \mathrm{sgn}\left (-\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1\right ) + \sqrt{-a} \log \left ({\left | -\sqrt{-a} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - a} \right |}\right ) \mathrm{sgn}\left (-\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1\right ) -{\left (2 \, \sqrt{a} \arctan \left (\frac{\sqrt{2} \sqrt{-a} + \sqrt{-a}}{\sqrt{a}}\right ) + \sqrt{-a} \log \left (\sqrt{2} \sqrt{-a} + \sqrt{-a}\right )\right )} \mathrm{sgn}\left (-\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1\right )}{d} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(d*x+c)*(-a-a*sin(d*x+c))^(1/2),x, algorithm="giac")

[Out]

(2*sqrt(a)*arctan(-(sqrt(-a)*tan(1/2*d*x + 1/2*c) - sqrt(-a*tan(1/2*d*x + 1/2*c)^2 - a))/sqrt(a))*sgn(-tan(1/2
*d*x + 1/2*c) - 1) + sqrt(-a)*log(abs(-sqrt(-a)*tan(1/2*d*x + 1/2*c) + sqrt(-a*tan(1/2*d*x + 1/2*c)^2 - a)))*s
gn(-tan(1/2*d*x + 1/2*c) - 1) - (2*sqrt(a)*arctan((sqrt(2)*sqrt(-a) + sqrt(-a))/sqrt(a)) + sqrt(-a)*log(sqrt(2
)*sqrt(-a) + sqrt(-a)))*sgn(-tan(1/2*d*x + 1/2*c) - 1))/d